Statistics for Points de Heegner et famille de courbes elliptiques E(t) : y² + txy + ty = x3 + 2tx eQ [x, y]
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| Points de Heegner et famille de courbes elliptiques E(t) : y² + txy + ty = x3 + 2tx eQ [x, y] | 0 |
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| April 2025 | 0 |
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| TH5121.pdf | 3 |